UIMenuController的基本用法

在项目中想要添加一个长按Cell弹出UIMenuController的功能，当我在tableview中添加时是可以弹出来的，然而当在自定义cell.m文件中添加UILongPressGestureRecognizer时，可以触发事件，但是MenuController死活不出来，捣鼓了半天无果，只好google搜索，最后发现忘记实现下面的第三个方法。下面把解决方案记录一下。

要实现长按弹出菜单栏需要做到以下三点：
1.在view（cell）或者viewController中调用-becomeFirstResponder方法；
2.你的view获得或者view controller需要实现 -canBecomeFirstResponder 方法,返回YES;
3.你的view获得或者view controller需要实现-canPerformAction:action withSender:sender 方法来隐藏或者现实响应的item；

cell中关键代码展示：

1.添加longpress事件

-(instancetype)initWithStyle:(UITableViewCellStyle)style reuseIdentifier:(NSString *)reuseIdentifier{if (self=[super initWithStyle:style reuseIdentifier:reuseIdentifier]) {[self addGestureRecognizer: [[UILongPressGestureRecognizer alloc]initWithTarget:selfaction:@selector(longTap:)]];}return self;}

2.处理长按事件

-(void)longTap:(UILongPressGestureRecognizer *)longRecognizer{if (longRecognizer.state==UIGestureRecognizerStateBegan) {[self becomeFirstResponder];UIMenuController *menu=[UIMenuController sharedMenuController];UIMenuItem *copyItem = [[UIMenuItem alloc] initWithTitle:@"复制" action:@selector(copyItemClicked:)];UIMenuItem *resendItem = [[UIMenuItem alloc] initWithTitle:@"转发"action:@selector(resendItemClicked:)];[menu setMenuItems:[NSArray arrayWithObjects:copyItem,resendItem,nil]];[menu setTargetRect:self.bounds inView:self];[menu setMenuVisible:YES animated:YES];}}

3.实现默认方法

#pragma mark 处理action事件-(BOOL)canPerformAction:(SEL)action withSender:(id)sender{if(action ==@selector(copyItemClicked:)){return YES;}else if (action==@selector(resendItemClicked:)){return YES;}return [super canPerformAction:action withSender:sender];}

#pragma mark  实现成为第一响应者方法-(BOOL)canBecomeFirstResponder{return YES;}

4.处理item点击事件

#pragma mark method-(void)resendItemClicked:(id)sender{NSLog(@"转发");//通知代理}

-(void)copyItemClicked:(id)sender{NSLog(@"复制");// 通知代理}