webapp应用Servlet
来源:互联网 发布:合肥行知 编辑:程序博客网 时间:2024/06/14 19:05
转:http://www.cnblogs.com/leiOOlei/p/3372521.html
1.首先修改pom.xml文件,添加servlet依赖
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd"> <modelVersion>4.0.0</modelVersion> <groupId>com.lei.demo</groupId> <artifactId>maven-web-demo</artifactId> <packaging>war</packaging> <version>0.0.1-SNAPSHOT</version> <name>maven-web-demo Maven Webapp</name> <url>http://maven.apache.org</url> <dependencies> <!-- JUnit配置 --> <dependency> <groupId>junit</groupId> <artifactId>junit</artifactId> <version>3.8.1</version> <scope>test</scope> </dependency> <!-- 添加Servlet --> <dependency> <groupId>javax.servlet</groupId> <artifactId>servlet-api</artifactId> <version>2.5</version> <scope>provided</scope> </dependency> </dependencies> <build> <finalName>maven-web-demo</finalName> </build></project>
修改完保存后,项目会从Maven仓库中自动添加servlet-api-2.5.jar包的引用,如果仓库中没有,会自动下载。
引用后见图。
2.新建一个Servlet
在src/main/java下创建一个Servlet,ServletDemo
package com.sulei.demo;import java.io.IOException;import javax.servlet.ServletException;import javax.servlet.http.HttpServlet;import javax.servlet.http.HttpServletRequest;import javax.servlet.http.HttpServletResponse;/** * Servlet implementation class ServletDemo */public class ServletDemo extends HttpServlet { private static final long serialVersionUID = 1L; public ServletDemo() { super(); } protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { doPost(request, response); } protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { request.setCharacterEncoding("UTF-8"); response.setContentType("text/html;charset=utf-8"); String action = request.getParameter("action"); if("login_input".equals(action)) { request.getRequestDispatcher("login.jsp").forward(request , response); } else if("login".equals(action)) { String name = request.getParameter("name"); String password = request.getParameter("password"); System.out.println("name->" + name + ",password->" + password); } }}
3.修改Web.xml
<?xml version="1.0" encoding="UTF-8"?><web-app xmlns:javaee="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <javaee:display-name>Archetype Created Web Application</javaee:display-name> <servlet> <javaee:description></javaee:description> <javaee:display-name>ServletDemo</javaee:display-name> <servlet-name>ServletDemo</servlet-name> <servlet-class>com.sulei.demo.ServletDemo</servlet-class> </servlet> <servlet-mapping> <servlet-name>ServletDemo</servlet-name> <url-pattern>/demo</url-pattern> </servlet-mapping></web-app>
4.创建index.jsp
<%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%><!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"><html><head><meta http-equiv="Content-Type" content="text/html; charset=UTF-8"><title>Insert title here</title></head><body> <p>用Maven创建web项目,测试Servlet</p> <a href="demo?action=login_input">登录(demo?action=login_input)</a></body></html>
5.创建login.jsp
<%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%><!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"><html><head><meta http-equiv="Content-Type" content="text/html; charset=UTF-8"><title>Insert title here</title></head><body> <form action="demo?action=login" method="post"> Name:<input type="text" name="name" /> Password:<input type="password" name="password" /> <input type="submit" value="登录" /> </form> </body></html>
OK,可以测试一下
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