1031. Hello World for U (20)【字符串处理】——PAT (Advanced Level) Practise

题目信息

1031. Hello World for U (20)

时间限制400 ms
内存限制65536 kB
代码长度限制16000 B

Given any string of N (>=5) characters, you are asked to form the characters into the shape of U. For example, “helloworld” can be printed as:

h  de  ll  rlowo

That is, the characters must be printed in the original order, starting top-down from the left vertical line with n1 characters, then left to right along the bottom line with n2 characters, and finally bottom-up along the vertical line with n3 characters. And more, we would like U to be as squared as possible – that is, it must be satisfied that n1 = n3 = max { k| k <= n2 for all 3 <= n2 <= N } with n1 + n2 + n3 - 2 = N.
Input Specification:

Each input file contains one test case. Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.

Output Specification:

For each test case, print the input string in the shape of U as specified in the description.

Sample Input:
helloworld!
Sample Output:

h   !e   dl   llowor

解题思路

字符串操作

AC代码

#include <stdio.h>#include <string.h>int main(){    char s[100];    scanf("%s", s);    int len = strlen(s);    int tl = (len + 2) / 3 - 1;    int sp = len - tl * 2 - 2;    int i = 0;    for (i = 0; i < tl; ++i){        putchar(s[i]);        int t = sp;        while (t-- > 0) putchar(' ');        putchar(s[len - 1 - i]);        putchar('\n');    }    for (;i < len - tl; ++i) putchar(s[i]);    putchar('\n');    return 0;}