Super Ugly Number

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Write a program to find the nth super ugly number.

Super ugly numbers are positive numbers whose all prime factors are in the given prime list primes of size k. For example, [1, 2, 4, 7, 8, 13, 14, 16, 19, 26, 28, 32] is the sequence of the first 12 super ugly numbers given primes = [2, 7, 13, 19] of size 4.

Note:
(1) 1 is a super ugly number for any given primes.
(2) The given numbers in primes are in ascending order.
(3) 0 < k ≤ 100, 0 < n ≤ 106, 0 < primes[i] < 1000.

用一个指针数组来记录每个质数乘积的次数,用另一个数字存储解。

时间复杂度O(nk),空间O(n)+O(k)

class Solution {public:    int nthSuperUglyNumber(int n, vector<int>& primes) {        int len = primes.size();        vector<int> point(len,0);        vector<int> ugly(n,INT_MAX);        ugly[0]=1;        for(int i=1; i<n; ++i){            for(int j=0; j<len; ++j)               ugly[i] = min(ugly[i],ugly[point[j]]*primes[j]);            for(int j=0; j<len; ++j)                if(ugly[i] == ugly[point[j]]*primes[j]){                    ++point[j];                }        }        return ugly[n-1];    }};

原文出自:http://blog.csdn.net/ciaoliang/article/details/50177735

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