[88][E][leetcode 题解]Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 
Given s = "Hello World",
return 5.

class Solution(object):    def lengthOfLastWord(self, s):        s = list(s)        if len(s) == 0:            return 0        s.reverse()        #print s        while len(s) > 0 and s[0] == ' ':            s = s[1:]        try:            pos = s.index(' ')        except:            return len(s)        return pos        """        :type s: str        :rtype: int        """