【M】【83】【leetcode题解】Flatten Binary Tree to Linked List

Given a binary tree, flatten it to a linked list in-place.

For example,
Given

         1        / \       2   5      / \   \     3   4   6

The flattened tree should look like:

   1    \     2      \       3        \         4          \           5            \             6

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两种办法，第一种比较难，被注释了，不是很懂。

第二种方法解释如下：

Note that the problem requires in-place operation.The flatten procedure is like: cut the left child and set to right, the right child is then linked to somewhere behind the left child. Where should it be then? Actually the right child should be linked to the most-right node of the left node. So the algorithm is as follows:

(1) store the right child (we call R)

(2) find the right-most node of left child

(3) set R as the right-most node's right child.

(4) set left child as the right child

(5) set the left child NULL

(6) set current node to current node's right child.

(7) iterate these steps until all node are flattened.

class Solution(object):    def __init__(self):        self.res = TreeNode(0)    def flatten(self, root):        if not root:            return        pre = None        while root:            if root.left:                pre = root.left                while pre.right:                    pre = pre.right                pre.right = root.right                root.right = root.left                root.left = None            root = root.right        '''    def flatten(self, root):        if not root:            return        self.flatten(root.right)        self.flatten(root.left)        root.right = self.res.right        root.left = None        self.res.right = root        '''