HDU 1048 字符串转化(整行读取函数cin.getline(str,100))
来源:互联网 发布:ug轮廓3d倒角编程技巧 编辑:程序博客网 时间:2024/04/30 15:19
Problem Description
Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar ever faced was keeping himself alive. In order for him to survive, he decided to create one of the first ciphers. This cipher was so incredibly sound, that no one could figure it out without knowing how it worked.
You are a sub captain of Caesar's army. It is your job to decipher the messages sent by Caesar and provide to your general. The code is simple. For each letter in a plaintext message, you shift it five places to the right to create the secure message (i.e., if the letter is 'A', the cipher text would be 'F'). Since you are creating plain text out of Caesar's messages, you will do the opposite:
Cipher text
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
Plain text
V W X Y Z A B C D E F G H I J K L M N O P Q R S T U
Only letters are shifted in this cipher. Any non-alphabetical character should remain the same, and all alphabetical characters will be upper case.
You are a sub captain of Caesar's army. It is your job to decipher the messages sent by Caesar and provide to your general. The code is simple. For each letter in a plaintext message, you shift it five places to the right to create the secure message (i.e., if the letter is 'A', the cipher text would be 'F'). Since you are creating plain text out of Caesar's messages, you will do the opposite:
Cipher text
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
Plain text
V W X Y Z A B C D E F G H I J K L M N O P Q R S T U
Only letters are shifted in this cipher. Any non-alphabetical character should remain the same, and all alphabetical characters will be upper case.
Input
Input to this problem will consist of a (non-empty) series of up to 100 data sets. Each data set will be formatted according to the following description, and there will be no blank lines separating data sets. All characters will be uppercase.
A single data set has 3 components:
Start line - A single line, "START"
Cipher message - A single line containing from one to two hundred characters, inclusive, comprising a single message from Caesar
End line - A single line, "END"
Following the final data set will be a single line, "ENDOFINPUT".
A single data set has 3 components:
Start line - A single line, "START"
Cipher message - A single line containing from one to two hundred characters, inclusive, comprising a single message from Caesar
End line - A single line, "END"
Following the final data set will be a single line, "ENDOFINPUT".
Output
For each data set, there will be exactly one line of output. This is the original message by Caesar.
Sample Input
STARTNS BFW, JAJSYX TK NRUTWYFSHJ FWJ YMJ WJXZQY TK YWNANFQ HFZXJXENDSTARTN BTZQI WFYMJW GJ KNWXY NS F QNYYQJ NGJWNFS ANQQFLJ YMFS XJHTSI NS WTRJENDSTARTIFSLJW PSTBX KZQQ BJQQ YMFY HFJXFW NX RTWJ IFSLJWTZX YMFS MJENDENDOFINPUT
Sample Output
IN WAR, EVENTS OF IMPORTANCE ARE THE RESULT OF TRIVIAL CAUSESI WOULD RATHER BE FIRST IN A LITTLE IBERIAN VILLAGE THAN SECOND IN ROMEDANGER KNOWS FULL WELL THAT CAESAR IS MORE DANGEROUS THAN HE
Source
South Central USA 2002
#include<iostream>#include<cstdio> #include<cstring>#include<algorithm>#include<cmath>using namespace std;char a[]="ABCDEFGHIJKLMNOPQRSTUVWXYZ";char b[]="VWXYZABCDEFGHIJKLMNOPQRSTU";char str[1000];int main(){int n,i,j;while(cin.getline(str,1000)) {if(strcmp(str,"ENDOFINPUT")==0) break;if(strcmp(str,"START")==0 || strcmp(str,"END")==0) continue;n=strlen(str);for(i=0;i<n;i++) {if(str[i]>='A'&&str[i]<='Z') cout<<b[str[i]-'A'];else cout<<str[i];}cout<<endl;}return 0;}
0 0
- HDU 1048 字符串转化(整行读取函数cin.getline(str,100))
- getline(cin,str) 函数分析
- cin cin.get() cin.getline() string类成员函数getline(cin,str)使用方法区别与联系
- C++ 输入函数getline(cin,str) 与cin.getline(str,int)区别
- C++ 输入函数getline(cin,str) 与cin.getline(str,int)区别
- C++ 输入函数getline(cin,str) 与cin.getline(str,int)区别
- c++中的cin,cin.get(),cin.getline()读取字符串
- 字符串输入方式总结(cin cin.get()cin.getline() getline())
- 字符串输入函数scanf,cin,cin.getline,gets,getline
- cin、cin.get()、cin.getline()、getline()、gets()等函数的用法(C++)
- cin、cin.get()、cin.getline()、getline()、gets()等函数的用法(转载)
- (转)cin、cin.get()、cin.getline()、getline()、gets()等函数的用法
- cin.get()与cin.getline()函数讲解1
- cin.getline().积累
- (VS2012)C++行输入函数的使用(scanf_s,cin.getline,cin.get)
- getline(cin,str)与cin.getline(str)的用法
- cin.get(line,ArSize) cin.getline(line,ArSize)和getline(cin,name)读取一行字符串区别
- 各种字符读取方法的比较(cin,getline等)
- 【Android 进阶(一)】Android MVP框架实现过程
- 单调队列 hdu3401 Trade
- R语言--tapply,sapply(因子和列表的操作)
- IOS中5种传值方式详解(属性、Block代码块、代理、单例、通知)
- javascript脚本从载入浏览器到显示执行的过程解析
- HDU 1048 字符串转化(整行读取函数cin.getline(str,100))
- Python yield 使用浅析
- CocoaPods入门 --小白篇
- CSS动画之硬件加速
- spring-session源码解读-4
- 理解RESTful架构
- 剑指offer:丑数
- 创建数据库的注解处理器_demo
- hdu 2795 线段树单点更新