HDOJ  2015   偶数求和

题目：

#include <stdio.h>
int main()
{
    intn,m,j,i,sum;
   while(scanf("%d%d",&n,&m)!=EOF)
    {
       sum=0;
       for(i=1,j=1;i<=n;j++,i++)
       {
           sum+=i*2;
           if(j==m&&i!=n)
           {
               printf("%d ",sum/j);
               sum=0;
               j=0;
           }
       }
       printf("%d\n",sum/(j-1));

    }
    return0;
}