leetcode (228) Summary Ranges js代码实现
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Summary Ranges
Given a sorted integer array without duplicates, return the summary of its ranges.
For example, given [0,1,2,4,5,7]
, return ["0->2","4->5","7"].
给出一个数组,找出其中连续的区间,比如例子中的,0到2为一个区间,4到5为一个区间
var summaryRanges = function(nums){var start = 0;var end = 0;var i = 0;var final = new Array();while(end != nums.length){while((nums[end] + 1) == nums[end + 1]){end++;}if(nums[end] == nums[start]){final[i] = String(nums[start]);}else{final[i] = nums[start] + "->" + nums[end];}i++;start = end + 1;end++;}return final;};
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