LeetCode 033 Search in Rotated Sorted Array

题目描述

Suppose a sorted array is rotated at some pivot unknown to you beforehand.

(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).

You are given a target value to search. If found in the array return its index, otherwise return -1.

You may assume no duplicate exists in the array.

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代码

    public int search(int[] nums, int target) {        int l = 0, r = nums.length - 1;        while (l <= r) {            int m = (l + r) / 2;            if (nums[m] == target)                return m;            if (nums[l] < nums[m]) {                if (target <= nums[m] && target >= nums[l])                    r = m - 1;                else                    l = m + 1;            } else if (nums[l] > nums[m]) {                if (target >= nums[l] || target <= nums[m])                    r = m - 1;                else                    l = m + 1;            } else                l++;        }        return -1;    }