LeetCode 228:Summary Ranges
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Given a sorted integer array without duplicates, return the summary of its ranges.
For example, given [0,1,2,4,5,7]
, return ["0->2","4->5","7"].
例如,给定数组[0,1,2,4,5,7] ,应当返回["0->2","4->5","7"] (即数组里所有连续数字的范围,如果只有一个则返回它本身)
题目不难,然而之前头脑不清晰,想了好久才想出来。。。用了两个下标start和end,end往后搜索直到不满足范围条件,然后分end-1是否等于start来决定往字符串里输入的结果。
class Solution {public: vector<string> summaryRanges(vector<int>& nums) { vector<string> vec; if(nums.size()==0) return vec; int start=0,end=0; while(end!=nums.size()) { string temp; for(end=start;end<nums.size();end++) if(nums[end]!=nums[start]+end-start) break; if((end-1)==start) { temp.append(to_string(nums[start])); vec.push_back(temp); } else { temp.append(to_string(nums[start])); temp.append("->"); temp.append(to_string(nums[end-1])); vec.push_back(temp); } start=end; } return vec; }};
好吧,最近做题变少了,一直在忙于各种实验,准备参加比赛的事,然后无人机也要开始弄了。。。我尽量本周内做完所有easy的题吧
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