UVA729 The Hamming Distance Problem
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题目扯了一大堆什么异或 XOR A B啊 都是没什么用的
根据重点和样例就知道题目给你两个N H N是指由N个数字 H是这个N个数字中有H个1(其他全是0)
接着要你给出这N个数字的排列(主题 是值得排列 不是位置的排列)
所以可以根据next_premutation()函数来做
开始的时候WA了5/6发都没过,仔细看了一遍代码是空格的问题
有些OJ对于输出的判断是很严格的!
#include<stdio.h>#include<algorithm>#include<math.h>#include<string.h>#include<iostream>using namespace std;int con[20];int main(){int n;scanf("%d",&n);while (n--){int n, h;scanf("%d%d", &n, &h);memset(con,0,sizeof(con));for (int i = n - h; i < n; i++){con[i] = 1;}do{for (int i = 0; i < n; i++)printf("%d", con[i]);cout << endl;} while (next_permutation(con,con+n));if (n > 0) printf("\n");}return 0;}
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