leetcode:190 Reverse Bits-每日编程第三十二题

来源:互联网 发布:吉利知豆d1和d2的区别 编辑:程序博客网 时间:2024/06/04 23:26

Reverse Bits

Total Accepted: 46760 Total Submissions: 160246 Difficulty: Easy

Reverse bits of a given 32 bits unsigned integer.

For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000).

Follow up:
If this function is called many times, how would you optimize it?

思路:

分块交换,对于8位数,abcdefgh->efghabcd->ghefcdab->hgfedcba。对于32位,同理。

<span style="font-size:14px;">class Solution {public:    uint32_t reverseBits(uint32_t n) {        n=(n<<16)|(n>>16);        n=(((n&0x00ff00ff)<<8)|((n&0xff00ff00)>>8));        n=(((n&0xf0f0f0f0)>>4)|((n&0x0f0f0f0f)<<4));        n=(((n&0x33333333)<<2)|((n&0xcccccccc)>>2));        n=(((n&0x55555555)<<1)|((n&0xaaaaaaaa)>>1));        return n;    }};</span>


0 0
原创粉丝点击