leetcode Coin Change

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You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money cannot be made up by any combination of the coins, return -1.

Example 1:
coins = [1, 2, 5], amount = 11
return 3 (11 = 5 + 5 + 1)

Example 2:
coins = [2], amount = 3
return -1.

Note:
You may assume that you have an infinite number of each kind of coin.

后续更新见原文：细语呢喃 > leetcode Coin Change

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java

public class Solution {    public int coinChange(int[] coins, int amount) {        int dp[] = new int[amount + 1];        final int INF = 0x7ffffffe;        for (int i = 1; i <= amount; i++) dp[i] = INF;        for (int i = 0; i <= amount; i++) {            for (int j = 0; j < coins.length; j++) {                if (i + coins[j] <= amount)                    dp[i + coins[j]] = Math.min(dp[i + coins[j]], dp[i] + 1);            }        }        return dp[amount] == INF ? -1 : dp[amount];    }}

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