HDU 1021 Fibonacci Again

Problem Description

There are another kind of Fibonacci numbers: F(0) = 7, F(1) = 11, F(n) = F(n-1) + F(n-2) (n>=2).

 

Input

Input consists of a sequence of lines, each containing an integer n. (n < 1,000,000).

 

Output

Print the word "yes" if 3 divide evenly into F(n).

Print the word "no" if not.

 

Sample Input

012345

 

Sample Output

nonoyesnonono

水，4个一周期，代码：

#include<iostream>using namespace std;int main(){int n;while(cin>>n){if(n%4==2)cout<<"yes"<<endl;else cout<<"no"<<endl;}return 0; }