NSSet使用小结

来源：互联网发布：超人软件编辑：程序博客网时间：2024/05/27 00:50

#import <Foundation/Foundation.h>
int main(int argc, const char * argv[])
{
@autoreleasepool {
NSSet *set1 = [NSSet setWithObjects:@"a", @"b", @"c", @"d", nil];
NSSet *set2 = [[NSSet alloc] initWithObjects:@"1", @"2", @"3", nil];
NSArray *array = [NSArray arrayWithObjects:@"a", @"b", @"c", nil];
NSSet *set3 = [NSSet setWithArray:array];
NSLog(@"set1 :%@", set1);
NSLog(@"set2 :%@", set2);
NSLog(@"set3 :%@", set3);
//获取集合个数
NSLog(@"set1 count :%d", set1.count);
//以数组的形式获取集合中的所有对象
NSArray *allObj = [set2 allObjects];
NSLog(@"allObj :%@", allObj);
//获取任意一对象
NSLog(@"anyObj :%@", [set3 anyObject]);
//是否包含某个对象
NSLog(@"contains :%d", [set3 containsObject:@"obj2"]);
//是否包含指定set中的对象
NSLog(@"intersect obj :%d", [set1 intersectsSet:set3]);
//是否完全匹配
NSLog(@"isEqual :%d", [set2 isEqualToSet:set3]);
//是否是子集合
NSLog(@"isSubSet :%d", [set3 isSubsetOfSet:set1]);
NSSet *set4 = [NSSet setWithObjects:@"a", @"b", nil];
NSArray *ary = [NSArray arrayWithObjects:@"1", @"2", @"3", @"4", nil];
NSSet *set5 = [set4 setByAddingObjectsFromArray:ary];
NSLog(@"addFromArray :%@", set5);
NSMutableSet *mutableSet1 = [NSMutableSet setWithObjects:@"1", @"2", @"3", nil];
NSMutableSet *mutableSet2 = [NSMutableSet setWithObjects:@"a", @"2", @"b", nil];
NSMutableSet *mutableSet3 = [NSMutableSet setWithObjects:@"1", @"c", @"b", nil];
//集合元素相减
[mutableSet1 minusSet:mutableSet2];
NSLog(@"minus :%@", mutableSet1);
//只留下相等元素
[mutableSet1 intersectSet:mutableSet3];
NSLog(@"intersect :%@", mutableSet1);
//合并集合
[mutableSet2 unionSet:mutableSet3];
NSLog(@"union :%@", mutableSet2);
//删除指定元素
[mutableSet2 removeObject:@"a"];
NSLog(@"removeObj :%@", mutableSet2);
//删除所有数据
[mutableSet2 removeAllObjects];
NSLog(@"removeAll :%@", mutableSet2);
}
return 0;
}

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