9. Remove Nth Node From End of List

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Given a linked list, remove the nth node from the end of list and return its head.

For example,

Given linked list: 1->2->3->4->5, and n = 2.

After removing the second node from the end, the linked list becomes 1->2->3->5.
Note:
Given n will always be valid.
Try to do this in one pass.

/** * Definition for singly-linked list. * public class ListNode { *     int val; *     ListNode next; *     ListNode(int x) { val = x; } * } */public class Solution {    public ListNode removeNthFromEnd(ListNode head, int n) {        ListNode start = new ListNode(0);        ListNode slow = start, fast = start;        slow.next = head;        //Move fast in front so that the gap between slow and fast becomes n        for(int i = 1; i <= n+1; i++)   {            fast = fast.next;        }    //Move fast to the end, maintaining the gap        while(fast != null) {            slow = slow.next;            fast = fast.next;        }    //Skip the desired node        slow.next = slow.next.next;        return start.next;    }}
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