.net 解析xml

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String  xml=

"<?xml version="1.0" encoding="utf-8"?>

<users>
<userid="1001">
<name>张三</name>
<email>123456789@136.com</email>
<phone>13400000000</phone>
</user>
<userid="1002">
<name>李四</name>
<email>123456789@126.com</email>
<phone>15800000000</phone>
</user>

</users>";


static void ReadParseXml(){ XmlDocument xmlDoc = new XmlDocument();

//获取xml文件地址 xmlDoc.Load("E:/Data/VisualStudio/C#/app001/ConsoleApp/App01/userlist.xml");

//加载xml字符串 string xml="........."

xmlDoc.Loadxml(xml); //查找<users> XmlNode root = xmlDoc.SelectSingleNode("users"); //获取到所有<users>的子节点 XmlNodeList nodeList =root.ChildNodes; //遍历所有子节点 foreach (XmlNode xn in nodeList) { XmlElement xe = (XmlElement)xn; XmlNodeList subList = xe.ChildNodes; foreach (XmlNode xmlNode in subList) { if ("name".Equals(xmlNode.Name)) { Console.WriteLine("姓名:" + xmlNode.InnerText); } else if ("email".Equals(xmlNode.Name)) { Console.WriteLine("邮箱:" + xmlNode.InnerText); } } }}

static void ReadParseXml2(){ XmlDocument xmlDoc = new XmlDocument(); xmlDoc.Load("E:/Data/VisualStudio/C#/app001/ConsoleApp/App01/userlist.xml"); //查找<users> XmlNode root = xmlDoc.SelectSingleNode("users"); //获取到所有<users>的子节点 XmlNodeList nodeList = xmlDoc.SelectSingleNode("users").ChildNodes; //遍历所有子节点 foreach (XmlNode xn in nodeList) { XmlElement xe = (XmlElement)xn; Console.WriteLine("节点的ID为: " + xe.GetAttribute("id")); XmlNodeList subList = xe.ChildNodes; foreach (XmlNode xmlNode in subList) { Console.WriteLine(xmlNode.InnerText); } }}

对XmlDocument类 的讲解,请看:http://www.cnblogs.com/kissdodog/archive/2013/02/24/2924236.html




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