HDU2061Treasure the new start, freshmen!

Treasure the new start, freshmen!

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 13874    Accepted Submission(s): 4219

Problem Description

background:
A new semester comes , and the HDU also meets its 50th birthday. No matter what's your major, the only thing I want to tell you is:"Treasure the college life and seize the time." Most people thought that the college life should be colorful, less presure.But in actual, the college life is also busy and rough. If you want to master the knowledge learned from the book, a great deal of leisure time should be spend on individual study and practise, especially on the latter one. I think the every one of you should take the learning attitude just as you have in senior school.
"No pain, No Gain", HDU also has scholarship, who can win it? That's mainly rely on the GPA(grade-point average) of the student had got. Now, I gonna tell you the rule, and your task is to program to caculate the GPA.
If there are K(K > 0) courses, the i-th course has the credit Ci, your score Si, then the result GPA is
GPA = (C1 * S1 + C2 * S2 +……+Ci * Si……) / (C1 + C2 + ……+ Ci……) (1 <= i <= K, Ci != 0)
If there is a 0 <= Si < 60, The GPA is always not existed.

 

Input

The first number N indicate that there are N test cases(N <= 50). In each case, there is a number K (the total courses number), then K lines followed, each line would obey the format: Course-Name (Length <= 30) , Credits(<= 10), Score(<= 100).
Notice: There is no blank in the Course Name. All the Inputs are legal

 

Output

Output the GPA of each case as discribed above, if the GPA is not existed, ouput:"Sorry!", else just output the GPA value which is rounded to the 2 digits after the decimal point. There is a blank line between two test cases. 

 

Sample Input

23Algorithm 3 97DataStruct 3 90softwareProject 4 852Database 4 59English 4 81

 

Sample Output

90.10Sorry!

 

题目大意就是：

一个新的学期开始了，但是我们要开始统计上个学期的课程成绩的学分绩点（GPA），每门课程的学分是 c，你的得分是 s，所以根据公式：GPA = (C1 * S1 + C2 * S2 +……+Ci * Si……) / (C1 + C2 + ……+ Ci……) (1 <= i <= K, Ci != 0)

就可以得到你的学分绩点了。但是如果你上个学期有一门课程挂科了（0<= s >60），也就是没有了学分绩点成绩了；

题目比较简单，但是在做的时候也是WA了好几次才发现；所以在这里提醒下小伙伴们需要注意的几点；

注意：

学分点题中没有说是 整型的，他的该门成绩的得分 题目中也没说是整型的，所以就要注意整型能不能过了的问题，可是我没有注意恩，最后亲测在这个地方wa了好几次才发现；改成浮点型的直接就ac了；

这里的话我是用结构体做的，只是因为好久没有用结构体了，练习下，别别忘了，你们也可以直接用数组变量做就OK了；

给出AC代码：

#include<iostream>using namespace std;#define MAX 1005struct node{char name[301];double grade;double score;}course[MAX];int main(){int n, k;int flag;double GPA, sum1, sum2;scanf("%d", &n);while (n--){sum1 = 0.0;sum2 = 0.0;flag = 1;scanf("%d", &k);for (int i = 0; i < k; i++){scanf("%s%lf%lf", &course[i].name, &course[i].grade, &course[i].score);if (course[i].score < 60 && course[i].score >= 0)flag = 0;sum1 += course[i].grade*course[i].score;sum2 += course[i].grade;}if (!flag) printf("Sorry!\n");else{GPA = sum1*1.0 / sum2;printf("%.2lf\n", GPA);}if (n)printf("\n");}return 0;}