re正则在python中的简单实用

python:2.7.3

platform:windows

最近公司需要做个分析,从冗长的错误日志中分析并且分离出同类的错误然后分别提交.

于是第一次接触python.然后就喜欢上了...

日志大概长这样.

20160101-190115[I]: [Lua]Role:19125 [ClientErrorMsg] [string "src/ui/office/KUIOfficeMainLayer.luac"]:0: attempt to index field '_mainLayout' (a nil value)  [C]:129stack:[string "src/main.luac"]: in function '__index'[string "src/ui/office/KUIOfficeMainLayer.luac"]: in function ''[string "src/ui/office/KUIOfficeMainLayer.luac"]: in main chunk[string "src/logic/KEventDispatchCenter.luac"]: in function 'dispatchEvent'[string "src/logic/KPlayer.luac"]: in main chunk[C]: in function 'xpcall'[string "src/network/KGameServer_v2.luac"]: in main chunk[string "src/network/KGameServer_v2.luac"]: in function 'OnRecvPackage'20160101-101537[I]: [Lua]Role:13603 [ClientErrorMsg] [string "lib/string.luac"]:0: assertion failed!  [C]:29stack:[string "src/main.luac"]: in main chunk[C]: in function 'assert'[string "lib/string.luac"]: in function 'split'[string "src/ui/guide/KUIGuideDialogueNode.luac"]: in function 'refreshDialogue'[string "src/ui/guide/KUIGuideDialogueNode.luac"]: in main chunk[string "src/ui/guide/KUIGuideDialogueNode.luac"]: in function 'refreshUI'[string "src/ui/uibase/KUINodeBase.luac"]: in function 'autoHandler'[string "src/ui/uibase/KUINodeBase.luac"]: in function 'init'[string "src/ui/g20160101-160554[I]: [Lua]Role:17096 [ClientErrorMsg] [string "src/ui/office/factory/KUIFactoryGearMultiChoo..."]:0: attempt to index global 'scrollControl' (a nil value)  [C]:26stack:[string "src/main.luac"]: in function '__index'[string "src/ui/office/factory/KUIFactoryGearMultiChoo..."]: in main chunk[string "src/logic/KEventDispatchCenter.luac"]: in function 'dispatchEvent'[string "src/logic/KPlayer.luac"]: in main chunk[C]: in function 'xpcall'[string "src/network/KGameServer_v2.luac"]: in main chunk[string "src/network/KGameServer_v2.luac"]: in function 'OnRecvPackage'[string "lib/tcp_client_v2.luac"]: in main chunk

观察了一阵子觉得首先应该把他们截断.于是正则就派上用场了.

由于反斜杠会引起排版错误。就贴图了。

通过这个去筛选分割.可以分割所有类似上文中类似20160101-160554[I]的字符串并且分别存储到values和devides中后面再去二次分析.

之后做工具的时候又遇见一个需求.

要实现正则查找一个字符串.该字符串是符合某个规则的字符串的子字符串.

一开始不知道有分组这一回事.只能分次去查找.

譬如

 <Size X="1280.0000" Y="720.0000" />                <PrePosition X="0.0000" Y="0.0000" />                <PreSize X="0.0000" Y="0.0000" />                <FileData Type="Normal" Path="ui_material/battle/zd_background.png" />

在类似的字符串中查找ui_material/battle/zd_background.png这个子字符串.

如果不使用分组的话.我必须先这样re.search(r'<FileData.*>', str).去定位到那一行.再在结果中二次查找.

后来问了我师傅他告诉我有分组这一回事..于是乎事情就简单了..

re.search(r'Path=\"(.*)\" />', str)

完美解决...

未完待续..