MYsql max求对应对大值的字段

MySQL中MAX函数与Group By一起使用的注意事项

mysql> select * from test;+----+-------+------+-------+| id | name  | age  | class |+----+-------+------+-------+|  1 | qiu   |   22 |     1 | |  2 | liu   |   42 |     1 | |  4 | zheng |   20 |     2 | |  3 | qian  |   20 |     2 | |  0 | wang  |   11 |     3 | |  6 | li    |   33 |     3 | +----+-------+------+-------+6 rows in set (0.00 sec)

如果想找到每个class里面的最大的age，则需要使用group by和max。

如下的sql语句，则输出结果有错误：

mysql> select id,name,max(age),class from test group by class;+----+-------+----------+-------+| id | name  | max(age) | class |+----+-------+----------+-------+|  1 | qiu   |       42 |     1 | |  4 | zheng |       20 |     2 | |  0 | wang  |       33 |     3 | +----+-------+----------+-------+3 rows in set (0.00 sec)

虽然找到的age是最大的age，但是与之匹配的用户信息却不是真实的信息，而是group by分组后的第一条记录的基本信息。

如果我使用以下的语句进行查找，则可以返回真实的结果。

mysql> select * from (  -> select * from test order by age desc) as b  -> group by class;+----+-------+------+-------+| id | name  | age  | class |+----+-------+------+-------+|  2 | liu   |   42 | 1 | |  4 | zheng |   20 | 2 | |  6 | li|   33 | 3 | +----+-------+------+-------+3 rows in set (0.00 s
查询一个表中类别字段中Max()最大值对应的记录
     select max(level) as level,role_name,account_id from( select * from role_data where account_id in ($str) order by level desc) as c;mysql>  select db_server,max(db_id) from (select * from rg_db_address where db_port in(6666,5555) order by db_id desc) as c group by db_id;select db_server,db_id from  rg_db_address as a where db_id =(select max(b.db_id) from rg_db_address as b where a.db_id = b.db_id and b.db_port in (4444,5555,6666));select id,kind,click_num from code as a   where  click_num=(select max(b.click_num)                    from code as b                    where a.kind = b.kind  and b.kind                  );  

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