hdu 1037 Keep on Truckin'

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=1037

Keep on Truckin'

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 11847    Accepted Submission(s): 8109

Problem Description

Boudreaux and Thibodeaux are on the road again . . .

"Boudreaux, we have to get this shipment of mudbugs to Baton Rouge by tonight!"

"Don't worry, Thibodeaux, I already checked ahead. There are three underpasses and our 18-wheeler will fit through all of them, so just keep that motor running!"

"We're not going to make it, I say!"

So, which is it: will there be a very messy accident on Interstate 10, or is Thibodeaux just letting the sound of his own wheels drive him crazy?

 

Input

Input to this problem will consist of a single data set. The data set will be formatted according to the following description.

The data set will consist of a single line containing 3 numbers, separated by single spaces. Each number represents the height of a single underpass in inches. Each number will be between 0 and 300 inclusive.

 

Output

There will be exactly one line of output. This line will be:

   NO CRASH

if the height of the 18-wheeler is less than the height of each of the underpasses, or:

   CRASH X

otherwise, where X is the height of the first underpass in the data set that the 18-wheeler is unable to go under (which means its height is less than or equal to the height of the 18-wheeler).
The height of the 18-wheeler is 168 inches.

 

Sample Input

180 160 170

 

Sample Output

CRASH 160

 

Source

South Central USA 2003

 

Recommend

We have carefully selected several similar problems for you:  1064 1056 1048 1036 1049 

题目大意：很水的一题。输出第一个不大于168的数。如果大于168则输出NO CRASH。

详见代码。

#include <iostream>#include <cstdio>using namespace std;int main(){    int a,b,c;    while (~scanf("%d%d%d",&a,&b,&c))    {        if (a>168&&b>168&&c>168)            printf ("NO CRASH\n");        if (a<=168)            printf ("CRASH %d\n",a);        else if (b<=168)            printf ("CRASH %d\n",b);        else if (c<=168)            printf ("CRASH %d\n",c);    }    return 0;}