Codeforces Round #338 (Div. 2):(615A)
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Vasya wants to turn on Christmas lights consisting of m bulbs. Initially, all bulbs are turned off. There aren buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is pressed, it turns on all the bulbs it's connected to. Can Vasya light up all the bulbs?
If Vasya presses the button such that some bulbs connected to it are already turned on, they do not change their state, i.e. remain turned on.
The first line of the input contains integers n andm (1 ≤ n, m ≤ 100) — the number of buttons and the number of bulbs respectively.
Each of the next n lines contains xi (0 ≤ xi ≤ m) — the number of bulbs that are turned on by thei-th button, and then xi numbers yij (1 ≤ yij ≤ m) — the numbers of these bulbs.
If it's possible to turn on all m bulbs print "YES", otherwise print "NO".
3 42 1 43 1 3 11 2
YES
3 31 11 21 1
NO
In the first sample you can press each button once and turn on all the bulbs. In the 2 sample it is impossible to turn on the 3-rd lamp.
/* problem:cf-615A *//* author: dang *//* date: 2016-1-25 10:45 *//* 题目大意: 1-m 数字全部出现,即YES ; 否则NO*/#include <cstdio>#include <cstring>int main(){ int n, m, flag = 0; int x, y, a[105]={0}; scanf("%d%d", &n, &m); while(n--){ scanf("%d", &x); while(x--){ scanf("%d", &y); a[y]=1; } } for(int i = 1; i <= m; i ++){ if(a[i]==0) flag = 1, i = m; } if(flag) printf("NO\n"); else printf("YES\n"); return 0;}
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