usaco1.2 transform 2008.11.5
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usaco1.2 transform 2008.11.5
{
ID:
PROG: transform
LANG: PASCAL
}
{刚开始,以为是一道很难的题,后来发现很简单。
只是我把镜面反射弄错了,我以为是沿x轴对称,结果是沿y轴对称。
其中,变量k还带成n了,找了半天的错,终于找到了 一定不要带错变量
还有,const n=10,这个总是忘了把它从调试的值改成最大值}
program kakashi; const n=10; type arr=array[1..n,1..n]of char; var i,j,k:longint; f1,f2:text; a,x,e:arr; flag:boolean; procedure deal(x1,x2:arr); var i,j:longint; si:boolean; begin si:=true; for i:=1 to k do for j:=1 to k do if x1[i,j]<>x2[i,j] then si:=false; if si then flag:=true; end; procedure try1(y:arr); var i,j:longint; begin for i:=1 to k do for j:=1 to k do x[i,j]:=y[k+1-j,i]; end; procedure try2(y:arr); var i,j:longint; begin for i:=1 to k do for j:=1 to k do x[i,j]:=y[k+1-i,k+1-j]; end; procedure try3(y:arr); var i,j:longint; begin for i:=1 to k do for j:=1 to k do x[i,j]:=y[j,i]; end; procedure try4(y:arr); var i,j:longint; begin for i:=1 to k do for j:=1 to k do x[i,j]:=y[i,k+1-j]; end; procedure try5(yy:arr); var tt:arr; i,j:longint; begin try4(yy); tt:=x; try1(tt); deal(x,e); if not(flag) then begin try2(tt); deal(x,e); if not(flag) then begin try3(tt); deal(x,e); end; end; end; begin assign(f1,'transform.in'); reset(f1); assign(f2,'transform.out'); rewrite(f2); readln(f1,k); for i:=1 to k do readln(f1,a[i]); for i:=1 to k do readln(f1,e[i]); flag:=false; try1(a); deal(x,e); if flag then writeln(f2,1) else begin try2(a); deal(x,e); if flag then writeln(f2,2) else begin try3(a); deal(x,e); if flag then writeln(f2,3) else begin try4(a); deal(x,e); if flag then writeln(f2,4) else begin try5(a); if flag then writeln(f2,5) else begin deal(a,e); if flag then writeln(f2,6) else writeln(f2,7) end; end; end; end; end; close(f1); close(f2); end.
data
TASK: transform
LANG: PASCAL
Compiling...
Compile: OK
Executing...
Test 1: TEST OK [0 secs]
Test 2: TEST OK [0.004 secs]
Test 3: TEST OK [0 secs]
Test 4: TEST OK [0.004 secs]
Test 5: TEST OK [0.004 secs]
Test 6: TEST OK [0 secs]
Test 7: TEST OK [0.004 secs]
Test 8: TEST OK [0.004 secs]
All tests OK.
Your program('transform') produced all correct answers! This is your
submission #7 forthis problem. Congratulations!
Here are the test data inputs:
------- test 1-------
3
---
---
---
---
-@-
---
------- test 2-------
5
-@@@-
-@@--
-@---
-----
-----
-----
----@
---@@
--@@@
-----
------- test 3-------
5
@@@@@
@---@
@@@@@
@@@@@
@@@@@
@@@@@
@@@@@
@@@@@
@---@
@@@@@
------- test 4-------
6
-@-@-@
@-@-@-
-@-@-@
@-@-@-
-@-@-@
@-@-@-
@-@-@-
-@-@-@
@-@-@-
-@-@-@
@-@-@-
-@-@-@
------- test 5-------
3
@@@
---
@@@
@@@
---
@@@
------- test 6-------
4
@@@@
@@@@
-@@@
@@@@
@@@@
@@@@
@@@-
@@@@
------- test 7-------
4
@-@@
@@@@
@@@@
@@@@
@@@@
@@@@
@@@@
@-@@
------- test 8-------
10
@--------@
----------
----------
----------
----------
----------
----------
----------
----------
----------
@---------
----------
----------
----------
----------
----------
----------
----------
----------
---------@
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