hdu1071 2010.3.5

hdu1071 2010.3.5

The area

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 2175    Accepted Submission(s): 1401

 

Problem Description

Ignatius bought a land last week, but hedidn't know the area of the land because the land is enclosed by a parabola anda straight line. The picture below shows the area. Now given all theintersectant points shows in the picture, can you tell Ignatius the area of theland?

 

Note: The point P1 in the picture is thevertex of the parabola. 

 

Input

The input contains several test cases. Thefirst line of the input is a single integer T which is the number of testcases. T test cases follow.

Each test case contains three intersectantpoints which shows in the picture, they are given in the order of P1, P2, P3.Each point is described by two floating-point numbers X andY(0.0<=X,Y<=1000.0).

 

Output

For each test case, you should output thearea of the land, the result should be rounded to 2 decimal places.

 

Sample Input

2

5.000000 5.000000

0.000000 0.000000

10.000000 0.000000

10.000000 10.000000

1.000000 1.000000

14.000000 8.222222

 

 

Sample Output

33.33

40.69

 

Hint

For float may be not accurate enough,please use double instead of float.

 

Author

Ignatius.L

#include <stdio.h>#include <math.h>double x1,x2,x3,y11,y2,y3,k,b,a;int i,t;double fun(double x){    return (a*x*x*x/3)-(a*x1+k/2)*x*x+(a*x1*x1+y11-b)*x;}void main(){    scanf("%d",&t);    for(i=1;i<=t;i++)    {        scanf("%lf %lf %lf %lf %lf %lf",&x1,&y11,&x2,&y2,&x3,&y3);        a=(y2-y11)/(x2-x1)/(x2-x1);        k=(y2-y3)/(x2-x3);        b=y2-k*x2;        printf("%.2lf\n",fun(x3)-fun(x2));    }}