1010. 一元多项式求导 (25)

题目：http://www.patest.cn/contests/pat-b-practise/1010

代码：

#include <stdio.h>int main(){  int n,k,flag=0;  while( scanf("%d %d",&n,&k)==2 )  {    if(k>0)    {      if(flag==0)      {        printf("%d %d",n*k,k-1);        flag = 1;      }      else        printf(" %d %d",n*k,k-1);    }    else      break;  }  if (flag==0)    printf("0 0");  return 0;}