hdu 1061 快速幂取模

Rightmost Digit

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 43858 Accepted Submission(s): 16494

Problem Description

Given a positive integer N, you should output the most right digit of N^N.

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains a single positive integer N(1<=N<=1,000,000,000).

Output

For each test case, you should output the rightmost digit of N^N.

Sample Input

234

Sample Output

76
Hint
In the first case, 3 * 3 * 3 = 27, so the rightmost digit is 7.In the second case, 4 * 4 * 4 * 4 = 256, so the rightmost digit is 6.
 

Author

Ignatius.L

import java.util.Scanner;public class Main{public static void main(String[] args) {// TODO Auto-generated method stubint n;int ans;int t;Scanner cin = new Scanner(System.in);t=cin.nextInt();while(t--!=0){ans=1;n=cin.nextInt();int b=n;while(b!=0){n=n%10;if(b%2==1)ans=ans*n%10;b=b/2;n=n*n%10;}System.out.println(ans);}}}