Leetcode 292
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Total Accepted: 46269 Total Submissions: 90128 Difficulty: Easy
You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to remove 1 to 3 stones. The one who removes the last stone will be the winner. You will take the first turn to remove the stones.
Both of you are very clever and have optimal strategies for the game. Write a function to determine whether you can win the game given the number of stones in the heap.
For example, if there are 4 stones in the heap, then you will never win the game: no matter 1, 2, or 3 stones you remove, the last stone will always be removed by your friend.
一行代码解决 ;bool canWinNim(int n) { return n % 4 != 0 ;}正如题目所说 ,只要为4的倍数,就一定输
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