【codevs1287】矩阵乘法（矩阵乘法）

题目描述

传送门

题解

矩阵乘法（暴力）。

代码

#include<iostream>#include<cstring>#include<cstdio>using namespace std;const int max_n=205;const int max_m=205;int n1,m1,n2,m2;int a[max_n][max_m],b[max_n][max_m],c[max_n][max_m];int main(){    scanf("%d%d",&n1,&m1);    for (int i=1;i<=n1;++i)      for (int j=1;j<=m1;++j)        scanf("%d",&a[i][j]);    scanf("%d%d",&n2,&m2);    for (int i=1;i<=n2;++i)      for (int j=1;j<=m2;++j)        scanf("%d",&b[i][j]);    for (int i=1;i<=n1;++i)      for (int j=1;j<=m2;++j)        for (int k=1;k<=n2;++k)          c[i][j]+=a[i][k]*b[k][j];    for (int i=1;i<=n1;++i)      for (int j=1;j<=m2;++j)        printf("%d%c",c[i][j]," \n"[j==m2]);}