数字转换成字符串

来源：互联网发布：优化蜜蜡图片编辑：程序博客网时间：2024/05/21 16:55

描述：

将一个int类型的数字转化为字符串，并判断有无重复字符串（长度应大于2）有返回1，无返回2。

代码：

#include <iostream>#define MAX 200using namespace std;int ltoAandRepeat(unsigned int num){char p1[MAX], p[MAX];int count = 0;int temp = num;//计算整数num几位数while (temp > 0){temp /= 10;count++;}//整数转换成字符串temp = num;int i;for (i = 0; i < count; i++){p1[i] = temp % 10+'0';temp /= 10;}for (i = 0; i < count; i++){p[count - 1 - i] = p1[i];}p[count] = '\0';cout << p<<endl;//判断有无重复字符串int n = 0;int j;for (i = 0; i < count - 1; i++){for (j = i + 1; j < count; j++){if (p[i] == p[j]&&j>=i+2)//不允许有重复的，如111不被认为是重复字符串// 如果允许，则if(p[i]==p[j])即可{if (p[++i] == p[++j])return 1;}}}return 2;}int main(){int num;cin >> num;cout << ltoAandRepeat(num) << endl;cin.get();cin.get();}

参考代码：

#include <iostream>using namespace std;#define MAX 200int ltoAandRepeat(unsigned int theNum, char*s){char str[MAX];char Repeat[MAX];int interg, remainder, i = 0, j , z = 0, k = 0, temp;//数字转换成字符串remainder = theNum % 10;interg = theNum / 10;while (interg){str[i] = remainder + 48;i++;remainder = interg % 10;interg = interg / 10;}str[i] = remainder + 48;i++;str[i] = '\0';for (z = 0, j = i - 1; j >= 0; j--, z++){s[z] = str[j];}s[z] = '\0';cout << theNum<<" has been transferred into a string: "<<s<<endl;for (i = 0; s[i] != '\0'; i++)// 判断有无重复字符串{for (j = 0; j < i; j++)// 判断之前是否出现过该字符{if (s[j] == s[i])// 若出现过，则从此位置开始向后判断有多少位重复{z = i;z++;j++;temp = 1;while (s[j] == s[z] && s[z] != '\0')// 实现可重叠的重复字符串// 实现无重叠的重复字符串，用while(s[j]==s[z]&&s[z]!='\0'&&j<i){z++;j++;temp++;}if (temp > 1){for (k = 0; k < temp; k++,i++){Repeat[k] = s[i];}Repeat[k] = '\0';cout << s << " has duplicated sub-string(s), which is " << Repeat << endl;return 1;}}}}return 2;}int main()// 主函数{int number, temp1, re;char s[MAX];//temp1=(cin >> number);temp1 = scanf("%d", &number);while (temp1 == 1)// 结束标志是EOF，即按Ctrl+C{re = ltoAandRepeat(number, s);cout << re << endl;printf("Please enter the next number: ");temp1 = scanf("%d", &number);}return 0;}

0 0