leetcode 9. Palindrome Number

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判断一个数是否为回文数，直接循环判断

class Solution(object):    def isPalindrome(self, x):        """        :type x: int        :rtype: bool        """        s = str(x)        lenS = len(s)                for i in range(0,lenS // 2):             if (s[i] != s[lenS - 1 - i]): return False        return True

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