HDU 2577 How to Type
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传送门:http://acm.hdu.edu.cn/showproblem.php?pid=2577
就是模拟打字,最后一定是大写锁定关掉,求最少的按键次数
dp,f[i][j] 0<=i<=n j=0或1表示到第i个字母大写锁定为关/开的最小按键数
转移方程:
s[i]为小写
f[i][0]=min(f[i-1][0]+1,f[i-1][1]+2);
f[i][1]=min(f[i-1][0]+2,f[i-1][1]+2);
s[i]为大写
f[i][0]=min(f[i-1][0]+2,f[i-1][1]+2);
f[i][1]=min(f[i-1][0]+2,f[i-1][1]+1);
初值 f[0][0]=0,f[0][1]=1;
代码如下:
#include<cstdio>#include<cstring>#include<iostream>using namespace std;int n;char ch[105];int s[105];int f[105][2];int main(){scanf("%d",&n);for (int i=1;i<=n;i++){scanf("%s",ch);int L=strlen(ch);for (int i=0;i<L;i++){if (ch[i]>='a' && ch[i]<='z'){s[i+1]=0;}else{s[i+1]=1;}}f[0][0]=0;f[0][1]=1;for (int i=1;i<=L;i++){if (!s[i]){f[i][0]=min(f[i-1][0]+1,f[i-1][1]+2);f[i][1]=min(f[i-1][0]+2,f[i-1][1]+2);}else{f[i][1]=min(f[i-1][0]+2,f[i-1][1]+1);f[i][0]=min(f[i-1][0]+2,f[i-1][1]+2);}}printf("%d\n",min(f[L][0],f[L][1]+1));}return 0;}
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