Hdu 1070 Milk【水】

Milk

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 17820 Accepted Submission(s): 4597

Problem Description

Ignatius drinks milk everyday, now he is in the supermarket and he wants to choose a bottle of milk. There are many kinds of milk in the supermarket, so Ignatius wants to know which kind of milk is the cheapest.

Here are some rules:
1. Ignatius will never drink the milk which is produced 6 days ago or earlier. That means if the milk is produced 2005-1-1, Ignatius will never drink this bottle after 2005-1-6(inclusive).
2. Ignatius drinks 200mL milk everyday.
3. If the milk left in the bottle is less than 200mL, Ignatius will throw it away.
4. All the milk in the supermarket is just produced today.

Note that Ignatius only wants to buy one bottle of milk, so if the volumn of a bottle is smaller than 200mL, you should ignore it.
Given some information of milk, your task is to tell Ignatius which milk is the cheapest.

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case starts with a single integer N(1<=N<=100) which is the number of kinds of milk. Then N lines follow, each line contains a string S(the length will at most 100 characters) which indicate the brand of milk, then two integers for the brand: P(Yuan) which is the price of a bottle, V(mL) which is the volume of a bottle.

Output

For each test case, you should output the brand of the milk which is the cheapest. If there are more than one cheapest brand, you should output the one which has the largest volume.

Sample Input

22Yili 10 500Mengniu 20 10004Yili 10 500Mengniu 20 1000Guangming 1 199Yanpai 40 10000

Sample Output

MengniuMengniu
Hint
In the first case, milk Yili can be drunk for 2 days, it costs 10 Yuan. Milk Mengniu can be drunk for 5 days, it costs 20 Yuan. So Mengniu is the cheapest.In the second case,milk Guangming should be ignored. Milk Yanpai can be drunk for 5 days, but it costs 40 Yuan. So Mengniu is the cheapest.

一道水题，只要题目看明白了，直接排个序就过了

这个月过年在家里，基本上没有做题，没办法，家里实在不适合学编程，本来想突破个位数的，结果怕是没突破，不过虽然没做太多题目，也学了一些知识点，这开学了，还是尽力投入学习吧！

#include<stdio.h>#include<string.h>#include<algorithm>using namespace std;const int maxn=0x3f3f3f3f;struct milk{char s[105];int money,vol,use;//总价钱和体积 double price;}x[105];bool cmp(milk a,milk b){if(a.price==b.price){return a.vol>b.vol;}return a.price<b.price;}int main(){int t;scanf("%d",&t);while(t--){int n;scanf("%d",&n);for(int i=0;i<n;++i){scanf("%s%d%d",x[i].s,&x[i].money,&x[i].vol);if(x[i].vol<200){x[i].price=maxn;}else{if(x[i].vol>1000)//最多喝五天！{x[i].price=x[i].money*1.0/5;}else{x[i].price=x[i].money*1.0/((x[i].vol/200));}}}sort(x,x+n,cmp);printf("%s\n",x[0].s);}return 0;}