1100. Mars Numbers (20)

来源：互联网发布：时差7小时知乎编辑：程序博客网时间：2024/05/17 04:35

考查进制转换

#include <iostream>#include <cstdio>using namespace std;string t1[] = {"tret", "jan", "feb", "mar", "apr", "may", "jun", "jly", "aug", "sep", "oct", "nov", "dec"};string t2[] = {"", "tam", "hel", "maa", "huh", "tou", "kes", "hei", "elo", "syy", "lok", "mer", "jou"};string num2mar(int n){string s;if(n > 12){s = t2[n/13];if(n%13){s += " " + t1[n%13];}}else{s = t1[n];}return s;}int mar2num(string s){int sum = 0;size_t pos = s.find(' ');for(int i = 1; i <= 12; ++i){if(t2[i] == s.substr(0, pos)){sum = 13*i;break;}}if(pos != string::npos){s = s.substr(pos+1);}for(int i = 0; i < 13; ++i){if(t1[i] == s){sum += i;break;}}return sum;}int main(){int n;(cin >> n).get();for(int i = 0; i < n; ++i){char c = cin.peek();if(c >= '0' && c <= '9'){int num;(cin >> num).get();cout << num2mar(num) << endl;}else{string s;getline(cin, s);cout << mar2num(s) << endl;}}return 0;}

0 0