C实现两个大数相加

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#include <stdio.h>#include <string.h>int main(){    char snum1[1024], snum2[1024], sop1[1024]="0", sop2[1024];    int len, len1, len2, opsign = 0;    printf( "输入两个操作数:\n" );    scanf( "%s\n%s", snum1, snum2 );    len1 = strlen( snum1 );    len2 = strlen( snum2 );    if( len1 >= len2 )    {         strcat( sop1, snum1 );         strcpy( sop2, snum2 );         len = len1 + 1;    }        else    {         strcat( sop1, snum2 );         strcpy( sop2, snum1 );         len = len2 + 1;    }        for( int i = 0; i != len; i++ )    {        int k = sop1[strlen(sop1)-1-i] - '0';        int m;        if( i >= strlen( sop2 ) ) m=0;        else m = sop2[strlen(sop2)-1-i] - '0';        if( opsign ) k++;        int n = k + m;        if( n >= 10 )        {             opsign = 1;             n = n - 10;            }            else        {                opsign = 0;            }        sop1[strlen(sop1)-1-i] = n + '0';    }     char* p=sop1;    if( sop1[0] == '0' ) printf( "两个操作数之和为:%s", ++p );    else  printf( "两个操作数之和为:%s", p );    getchar();    getchar();    return 0;}

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