1002. A+B for Polynomials (25)

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1002. A+B for Polynomials (25)

时间限制
400 ms
内存限制
65536 kB
代码长度限制
16000 B
判题程序
Standard
作者
CHEN, Yue

This time, you are supposed to find A+B where A and B are two polynomials.

Input

Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, where K is the number of nonzero terms in the polynomial, Ni and aNi (i=1, 2, ..., K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10,0 <= NK < ... < N2 < N1 <=1000.

Output

For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.

Sample Input
2 1 2.4 0 3.22 2 1.5 1 0.5
Sample Output
3 2 1.5 1 2.9 0 3.2

题意:

给你两个多项式,输出相加后的多项式


考点:

1. 格式化输出:setprecision();


坑点:


#include <iostream>#include <iomanip>using namespace std;int main(){    double n[1001];    int m, e;    double c;        for(int i = 0; i < 1001; i++) n[i] = 0;        for(int t = 0; t < 2; t++)    {            cin >> m;            for(int i = 0; i < m; i++)            {                  cin >> e >> c;                  n[e] += c;            }    }        int num = 0;        for(int i = 0; i < 1001; i++)            if(n[i] != 0) num++;    cout << num;    for(int i = 1000; i >= 0; i--)            if(n[i] != 0) cout << " " << i << " " << setiosflags(ios::fixed) << setprecision(1) << n[i];    cout << endl;}


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