PAT-Course List for Student (25)
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题意:
模拟课程统计
解答:
本题和PAT-Student for Course List需求相反,那题用了一个ArrayList里面套了几个ArrayList,本题由于要有名字(String)作为索引,所以使用HashMap,再在里面套一个ArrayList。
具体的java代码:
import java.util.*;public class Main{ public static void main(String[] args){ Scanner in=new Scanner(System.in); int N=in.nextInt(); int K=in.nextInt(); HashMap<String,ArrayList<Integer>> map=new HashMap<String,ArrayList<Integer>>(); for(int i=0;i<K;i++){ int c=in.nextInt(); int num=in.nextInt(); for(int j=0;j<num;j++){ String name=in.next(); if(map.get(name)==null){ map.put(name,new ArrayList<Integer>()); } map.get(name).add(c); } } for(int i=0;i<N;i++){ String temp=in.next(); System.out.print(temp+" "); ArrayList<Integer> list=map.get(temp); if(list==null) { System.out.println(0); continue; } System.out.print(list.size()); Collections.sort(list); for(int j=0;j<list.size();j++){ System.out.print(" "+list.get(j)); } System.out.println(); } in.close(); } }
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