[leetcode] 83. Remove Duplicates from Sorted List
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Given a sorted linked list, delete all duplicates such that each element appear only once.
For example,
Given 1->1->2
, return 1->2
.
Given 1->1->2->3->3
, return 1->2->3
.
这道题是删除已排序链表中重复值的节点,题目难度为Easy。
这样的题目一般需要记录下前一节点(pre),如果当前节点(cur)值和前一节点值相等,删除当前节点(pre->next = cur->next),否则更新前一节点为当前节点(pre = cur),这样遍历链表即可删除所有重复值的节点。具体代码:
class Solution {public: ListNode *deleteDuplicates(ListNode *head) { if(!head) return NULL; ListNode* cur = head->next; ListNode* pre = head; while(cur) { if(cur->val == pre->val) pre->next = cur->next; else pre = cur; cur = cur->next; } return head; }};
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