1108. Finding Average (20)

时间限制

400 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

The basic task is simple: given N real numbers, you are supposed to calculate their average. But what makes it complicated is that some of the input numbers might not be legal. A "legal" input is a real number in [-1000, 1000] and is accurate up to no more than 2 decimal places. When you calculate the average, those illegal numbers must not be counted in.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (<=100). Then N numbers are given in the next line, separated by one space.

Output Specification:

For each illegal input number, print in a line "ERROR: X is not a legal number" where X is the input. Then finally print in a line the result: "The average of K numbers is Y" where K is the number of legal inputs and Y is their average, accurate to 2 decimal places. In case the average cannot be calculated, output "Undefined" instead of Y. In case K is only 1, output "The average of 1 number is Y" instead.

Sample Input 1:

75 -3.2 aaa 9999 2.3.4 7.123 2.35

Sample Output 1:

ERROR: aaa is not a legal numberERROR: 9999 is not a legal numberERROR: 2.3.4 is not a legal numberERROR: 7.123 is not a legal numberThe average of 3 numbers is 1.38

Sample Input 2:

2aaa -9999

Sample Output 2:

ERROR: aaa is not a legal numberERROR: -9999 is not a legal numberThe average of 0 numbers is Undefined

#include <iostream>#include <string>#include <vector>#include <cstdlib>using namespace std;int main(){string s;int n,cnt=0;double avg=0;cin>>n;for(int i=0;i<n;i++){cin>>s;bool legal = true;bool dot_cnt = 0;for(int i=0;i<s.size();i++){if(!(s[i]>= '0' && s[i] <= '9') && s[i] != '-' && s[i] != '.'){legal = false;break;}if(s[i] == '.'){if(s.size() - i > 3){legal = false;break;}dot_cnt++;if(dot_cnt >= 2){legal = false;break;}}}if(legal == true){double a = (double)strtod(s.c_str(),NULL);if(a > 1000 || a<-1000){cout<<"ERROR: "<<s<<" is not a legal number\n";continue;}avg += a;cnt++;}elsecout<<"ERROR: "<<s<<" is not a legal number\n";}if(cnt != 0){if(cnt == 1)printf("The average of 1 number is %.2lf\n",avg/cnt);else printf("The average of %d numbers is %.2lf\n",cnt,avg/cnt);}else cout<<"The average of 0 numbers is Undefined\n";system("pause");return 0;}

用strtol直接简化步骤，又做了一遍这道题发现破绽还挺多的，首先题目里没有规定.xx 或 xx.是不是合法的，还有 3e1这样的科学计数法表示的小数是不是合法的。

而下面的这种方法忽略了上面的情况也能通过。

<pre name="code" class="cpp">#include <iostream>#include <string>#include <cstdlib>using namespace std;int main(){int n,cnt = 0;cin>>n;string num;double sum = 0.0;for(int i=0;i<n;i++){cin>>num;char * pos;double value = strtod(num.c_str(),&pos);bool ok = true;if(*pos != '\0')ok = false;if(value<-1000 || value >1000)ok = false;int lpos = num.find_last_of(".");if(lpos != string::npos) if(num.size() - lpos > 3)ok = false;if(ok){cnt++;sum += value;}elseprintf("ERROR: %s is not a legal number\n",num.c_str());}if(cnt != 0){if(cnt != 1)printf("The average of %d numbers is %.2lf\n",cnt,sum/cnt);else printf("The average of 1 number is %.2lf\n",sum);}else cout<<"The average of 0 numbers is Undefined\n";return 0;}