Oulipo (HDU_1686) KMP
来源:互联网 发布:mac安装磁盘被锁定 编辑:程序博客网 时间:2024/06/05 22:52
Oulipo
Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 8934 Accepted Submission(s): 3614
Problem Description
The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book:
Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…
Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces.
So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A', 'B', 'C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.
Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…
Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces.
So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A', 'B', 'C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.
Input
The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:
One line with the word W, a string over {'A', 'B', 'C', …, 'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W).
One line with the text T, a string over {'A', 'B', 'C', …, 'Z'}, with |W| ≤ |T| ≤ 1,000,000.
One line with the word W, a string over {'A', 'B', 'C', …, 'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W).
One line with the text T, a string over {'A', 'B', 'C', …, 'Z'}, with |W| ≤ |T| ≤ 1,000,000.
Output
For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T.
Sample Input
3BAPCBAPCAZAAZAZAZAVERDIAVERDXIVYERDIAN
Sample Output
130
题目大意:字符串匹配。给出主串和模式串,求可以从主串中匹配出多少模式串。
解题思路:KMP。在kmp函数中,每成功匹配一次,计数加一,并且将j = next[j];
代码如下:
#include"iostream"#include"cstdio"#include"cstring"using namespace std;const int maxn = 1000005;const int maxm = 10005;char s[maxn],p[maxm];int Next[maxm];void MakeNext(int m){Next[0] = -1;//-1 表示没有已匹配的串中没有符合要要求的 int i = 0,j = -1;//i表示主串的指针,j表示模式串的指针 while(i < m){//i不回溯,不断向后移动 if(j == -1 || p[i] == p[j]){ i ++ , j ++;//两串当前位置相等,比较下一位 if(p[i] != p[j]) Next[i] = j;else Next[i] = Next[j];}else j = Next[j];}}int KMP(int n,int m){int i = 0,j = 0,cnt = 0;while(i < n && j < m){if(s[i] == p[j] || j == -1){i ++,j ++;if(j == m){//成功匹配 cnt ++;j = Next[j];}}else j = Next[j];}return cnt;}int main(){int n,m,cas;scanf("%d",&cas);while(cas --){scanf("%s%s",&p,&s);n = strlen(s);m = strlen(p);if(m > n) printf("0\n");else{MakeNext(m);printf("%d\n",KMP(n,m));}}return 0;}
0 0
- Oulipo (HDU_1686) KMP
- hdu_1686 Oulipo
- KMP:Oulipo
- Oulipo +KMP
- Oulipo KMP
- KMP Oulipo
- Oulipo KMP
- 3461 Oulipo //KMP
- HDU 1686 Oulipo (kmp)
- poj Oulipo(KMP)
- poj 3461 Oulipo(KMP)
- (简单kmp) Oulipo (p3461)
- 【KMP】 poj3461 Oulipo
- 【KMP】Oulipo POJ3461
- hdu 1686 kmp Oulipo
- poj3461 Oulipo (kmp)
- POJ 3461 Oulipo(KMP)
- KMP hdu-1686-Oulipo
- 态度
- Android-改变文字颜色的上下文菜单
- 拒绝被坑 超实用的移动电源选购技巧 分享给大家
- windows客户端开发--duilib显示html
- Java多线程安全问题及解决方案
- Oulipo (HDU_1686) KMP
- 动态HTML和W3C文档对象模型
- 精简ID号码
- 特征提取算法--Surf
- 数据结构(12)线性表之C++实现一元多项式相加
- 添加Push失败!(与alias对应的device_tokens为空)
- UESTC 1146 秋实大哥与连锁快餐店 最小生成树、Prim
- Storm实战常见问题及解决方案
- Codeforces 8VC Venture Cup