poj1477 box of bricks
来源:互联网 发布:数据分析师有前途吗 编辑:程序博客网 时间:2024/05/18 11:28
//这题只是让你求给出的数的平均数即可!再通过续一比较,不够平均数的就从多于平均数中补上! 简单的题目! #include <iostream>using namespace std;int num[55];int main(){ int n, i, tc = 0, sum, avg, ans; while (cin >> n) { if (n == 0) break; tc++; sum = ans = 0; for (i = 0; i < n; i++) { cin >> num[i]; sum += num[i]; } avg = sum / n; for (i = 0; i < n; i++) { if (num[i] > avg) ans += num[i] - avg; } cout << "Set #" << tc << endl << "The minimum number of moves is " << ans << "." << endl << endl; }}
0 0
- poj1477 Box of Bricks
- poj1477 box of bricks
- 12 POJ1477 Box of Bricks
- poj1477 Box of Bricks 贪心大水题
- Box of Bricks
- 1477 Box of Bricks
- 1477:Box of Bricks
- 1477 Box of Bricks
- 591 - Box of Bricks
- HDOJ1326 Box of Bricks
- HDU1326:Box of Bricks
- 591 - Box of Bricks
- 591 - Box of Bricks
- UVA591- Box of Bricks
- BNU Box of Bricks
- Box of Bricks
- hdu1326 Box of Bricks
- Box of Bricks
- uvalive4987
- Java并发编程:线程间协作的两种方式:wait、notify、notifyAll和Condition
- 【图像处理】图形图像中术语
- RxSwift(一)
- A*算法
- poj1477 box of bricks
- angularjs,ng-include引入html代码片段
- UNICODE与ANSI的区别【转】
- hbase 新版本 java api 遍历
- 【转载自百度百科】this的用法
- 【VIM]:简明Vim练级攻略
- spring事务管理几种方式(转)
- msyql 备份sql文件及恢复
- 【Java】数组属性的例子