HDU 3466 Proud Merchants

Proud Merchants

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/65536 K (Java/Others)
Total Submission(s): 4334    Accepted Submission(s): 1788

Problem Description

Recently, iSea went to an ancient country. For such a long time, it was the most wealthy and powerful kingdom in the world. As a result, the people in this country are still very proud even if their nation hasn’t been so wealthy any more.
The merchants were the most typical, each of them only sold exactly one item, the price was Pi, but they would refuse to make a trade with you if your money were less than Qi, and iSea evaluated every item a value Vi.
If he had M units of money, what’s the maximum value iSea could get?

 

Input

There are several test cases in the input.

Each test case begin with two integers N, M (1 ≤ N ≤ 500, 1 ≤ M ≤ 5000), indicating the items’ number and the initial money.
Then N lines follow, each line contains three numbers Pi, Qi and Vi (1 ≤ Pi ≤ Qi ≤ 100, 1 ≤ Vi ≤ 1000), their meaning is in the description.

The input terminates by end of file marker.

 

Output

For each test case, output one integer, indicating maximum value iSea could get.

 

Sample Input

2 1010 15 105 10 53 105 10 53 5 62 7 3

 

Sample Output

511

 

Author

iSea @ WHU

 

Source

2010 ACM-ICPC Multi-University Training Contest（3）——Host by WHU

 

Recommend

zhouzeyong   |   We have carefully selected several similar problems for you:  3460 3463 3468 3467 3465 

 这道需要排序，不过刚开始做时虽然知道要排序，不过在排序时把按什么样的顺序排搞错了

#include<stdio.h>#include<string.h>#include<algorithm>using namespace std;struct node{int p,q,v;}t[11000];bool cmp(node a,node b){return a.q-a.p<b.q-b.p;//相差最小时才是最优 }int main(){int n,m,i,j,ans[11000];while(scanf("%d%d",&n,&m)!=EOF){for(i=1;i<=n;i++)scanf("%d%d%d",&t[i].p,&t[i].q,&t[i].v);sort(t+1,t+n+1,cmp);memset(ans,0,sizeof(ans));for(i=1;i<=n;i++)for(j=m;j>=t[i].q;j--)ans[j]=max(ans[j],ans[j-t[i].p]+t[i].v);printf("%d\n",ans[m]);}return 0; }