hdoj A + B Again 2057 （16进制加法）

A + B Again

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 21579    Accepted Submission(s): 9325

Problem Description

There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !

 

Input

The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.

 

Output

For each test case,print the sum of A and B in hexadecimal in one line.

 

Sample Input

+A -A+1A 121A -9-1A -121A -AA

 

Sample Output

02C11-2C-90
#include<stdio.h>#include<string.h>#include<math.h>#include<algorithm>#include<iostream>#define INF 0x3f3f3f3f#define ull unsingned long long#define ll long long#define IN __int64#define N 10010#define M 1000000007using namespace std;int main(){IN a,b;while(scanf("%I64X %I64X",&a,&b)!=EOF){a+=b;int flag=0;if(a<0){a=-a;flag=1;}if(!flag)printf("%I64X\n",a);elseprintf("-%I64X\n",a);}return 0;}