十进制的转换

#include <stdio.h>int main (void){const char baseDigits[16] = {'0', '1', '2', '3', '4', '5', '6', '7','8', '9', 'A', 'B', 'C', 'D', 'E', 'F' };int convertedNumber[64];long int numberToConvert;int nextDigit, base, index = 0;// get the number and the baseprintf ("Number to be converted? ");scanf ("%ld", &numberToConvert);printf ("Base? ");scanf ("%i", &base);// convert to the indicated basedo {convertedNumber[index] = numberToConvert % base;++index;numberToConvert = numberToConvert / base;Character Arrays 111}while ( numberToConvert != 0 );// display the results in reverse orderprintf ("Converted number = ");for (--index; index >= 0; --index ) {nextDigit = convertedNumber[index];printf ("%c", baseDigits[nextDigit]);}printf ("\n");return 0;}

Program 7.7 Output
Number to be converted? 10
Base? 2
Converted number = 1010
Program 7.7 Output (Rerun)
Number to be converted? 128362
Base? 16
Converted number = 1F56A

1.取余数，放进数组，但为逆序
2. 创建一个字符数组16位，放进16base所有数字对应的字母
3.逆序输出时，令nextdigit等于数组中的一个余数，对应字符数组的字符输出即可。
4.对base应该有个判断：若base为零则run time error；base=1则进入无限循环；base超过16则要扩展数组16.