iOS去除数组重复元素
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经过面试时问到这个题目,回答了几种方法,足够简单了,结果面试官要求一行代码搞定。呵呵哒!我当时确实不清楚最后最简单的答案,但是感觉没必要这么苛刻的。
转载地址:http://blog.csdn.net/wm9028/article/details/49926535
第一种:利用NSDictionary的AllKeys(AllValues)方法
代码:
- NSArray *dataArray = @[@"2014-04-01",@"2014-04-02",@"2014-04-03",
- @"2014-04-01",@"2014-04-02",@"2014-04-03",
- @"2014-04-01",@"2014-04-03",@"2014-04-03",
- @"2014-04-01",@"2014-04-02",@"2014-04-03",
- @"2014-04-01",@"2014-04-02",@"2014-04-03",
- @"2014-04-01",@"2014-04-02",@"2014-04-03",
- @"2014-04-04",@"2014-04-06",@"2014-04-08",
- @"2014-04-05",@"2014-04-07",@"2014-04-09",];
- NSMutableDictionary *dic = [[NSMutableDictionary alloc]initWithCapacity:0];
- for(NSString *str in dataArray)
- {
- [dic setValue:str forKey:str];
- }
- NSLog(@"%@",[dic allKeys]);
打印结果:
(
"2014-04-09",
"2014-04-02",
"2014-04-08",
"2014-04-01",
"2014-04-07",
"2014-04-06",
"2014-04-05",
"2014-04-04",
"2014-04-03"
)
第二种方法:利用NSSet的AllObjects方法
实例代码:
- NSArray *dataArray = @[@"2014-04-01",@"2014-04-02",@"2014-04-03",
- @"2014-04-01",@"2014-04-02",@"2014-04-03",
- @"2014-04-01",@"2014-04-03",@"2014-04-03",
- @"2014-04-01",@"2014-04-02",@"2014-04-03",
- @"2014-04-01",@"2014-04-02",@"2014-04-03",
- @"2014-04-01",@"2014-04-02",@"2014-04-03",
- @"2014-04-04",@"2014-04-06",@"2014-04-08",
- @"2014-04-05",@"2014-04-07",@"2014-04-09",];
- NSSet *set = [NSSet setWithArray:dataArray];
- NSLog(@"%@",[set allObjects]);
打印结果:
(
"2014-04-01",
"2014-04-02",
"2014-04-03",
"2014-04-04",
"2014-04-06",
"2014-04-08",
"2014-04-05",
"2014-04-07",
"2014-04-09"
)
第三种方法,利用数组的containsObject来去除
代码如下:
- NSArray *dataArray = @[@"2014-04-01",@"2014-04-02",@"2014-04-03",
- @"2014-04-01",@"2014-04-02",@"2014-04-03",
- @"2014-04-01",@"2014-04-03",@"2014-04-03",
- @"2014-04-01",@"2014-04-02",@"2014-04-03",
- @"2014-04-01",@"2014-04-02",@"2014-04-03",
- @"2014-04-01",@"2014-04-02",@"2014-04-03",
- @"2014-04-04",@"2014-04-06",@"2014-04-08",
- @"2014-04-05",@"2014-04-07",@"2014-04-09",];
- NSMutableArray *listAry = [[NSMutableArray alloc]init];
- for (NSString *str in dataArray) {
- if (![listAry containsObject:str]) {
- [listAry addObject:str];
- }
- }
- NSLog(@"%@",listAry);
打印结果:
(
"2014-04-01",
"2014-04-02",
"2014-04-03",
"2014-04-04",
"2014-04-06",
"2014-04-08",
"2014-04-05",
"2014-04-07",
"2014-04-09"
)
第四种方法:利用keyValue的方式(自己不是太明白)
- NSArray *dataArray = @[@"2014-04-01",@"2014-04-02",@"2014-04-03",
- @"2014-04-01",@"2014-04-02",@"2014-04-03",
- @"2014-04-01",@"2014-04-03",@"2014-04-03",
- @"2014-04-01",@"2014-04-02",@"2014-04-03",
- @"2014-04-01",@"2014-04-02",@"2014-04-03",
- @"2014-04-01",@"2014-04-02",@"2014-04-03",
- @"2014-04-04",@"2014-04-06",@"2014-04-08",
- @"2014-04-05",@"2014-04-07",@"2014-04-09",];
- dataArray = [dataArray valueForKeyPath:@"@distinctUnionOfObjects.self"];
- NSLog(@"%@",dataArray);
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