POJ 3061 Subsequence

Subsequence

Time Limit: 1000MS Memory Limit: 65536KTotal Submissions: 11102 Accepted: 4604

Description

A sequence of N positive integers (10 < N < 100 000), each of them less than or equal 10000, and a positive integer S (S < 100 000 000) are given. Write a program to find the minimal length of the subsequence of consecutive elements of the sequence, the sum of which is greater than or equal to S.

Input

The first line is the number of test cases. For each test case the program has to read the numbers N and S, separated by an interval, from the first line. The numbers of the sequence are given in the second line of the test case, separated by intervals. The input will finish with the end of file.

Output

For each the case the program has to print the result on separate line of the output file.if no answer, print 0.

Sample Input

210 155 1 3 5 10 7 4 9 2 85 111 2 3 4 5

Sample Output

23

Source

Southeastern Europe 2006

给出N个数，求最短子串和大于S

周赛题上说是二分，怎么感觉好像不是

#include<stdio.h>#include<string.h>#include<algorithm>using namespace std;int main(){int t,n,s,i,j,num[110000];scanf("%d",&t);while(t--){scanf("%d%d",&n,&s);memset(num,0,sizeof(num));for(i=0;i<n;i++)scanf("%d",&num[i]);int l,r;bool flag=false;int minn=0xfffffff;l=r=0;int sum=0;while(r<n){sum+=num[r++];while(sum>=s)//找到之后更新最优解 {flag=true;minn=min(minn,r-l);sum-=num[l++];}}if(flag)printf("%d\n",minn);elseprintf("0\n");}return 0;}