LeetCode 165 Compare Version Numbers

Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

别看题目那么长，就是简单的比较版本号大小。Java有split方法所以。。。

public static int compareVersion(String version1, String version2) {String[] nums1 = version1.split("\\.");String[] nums2 = version2.split("\\.");for (int i = 0; i < Math.max(nums1.length, nums2.length); i++) {int num1 = i < nums1.length ? Integer.valueOf(nums1[i]) : 0;int num2 = i < nums2.length ? Integer.valueOf(nums2[i]) : 0;if (num1 > num2) return 1;if (num1 < num2) return -1;}return 0;}