1002. A+B for Polynomials (25)

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This time, you are supposed to find A+B where A and B are two polynomials.

Input

Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, where K is the number of nonzero terms in the polynomial, Ni and aNi (i=1, 2, ..., K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10,0 <= NK < ... < N2 < N1 <=1000.

Output

For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.

Sample Input
2 1 2.4 0 3.22 2 1.5 1 0.5
Sample Output
3 2 1.5 1 2.9 0 3.2

//要考虑所有的情况,第一个多项式为零,和第二个多项式为零,以及两个想加为零的情况#include<iostream>#include<vector>#include <iomanip>using namespace std;typedef struct plo{int expo;float coef;}plo;int main(){vector<plo> vec1;vector<plo>::iterator iter;int expo,num1=0,num11=0,num2=0,flag=0,flag1=1;float coef;cin>>num1;num11=num1;while(num11>0){plo plo1;cin>>plo1.expo>>plo1.coef;vec1.push_back(plo1);num11--;}cin>>num2;while(num2>0){flag1=1;flag=0;cin>>expo>>coef;if(num1==0)//如果第一个多项式为零,则将第二个多项式所有的都存入向量{plo plo1;plo1.expo=expo;plo1.coef=coef;vec1.push_back(plo1);}else{for(int i=0;i<vec1.size();i++)//分三种情况,第一种就是第二个多项式中的一个项在第一个多项式中有相同的项{if((vec1[i]).expo==expo){(vec1[i]).coef+=coef;if(vec1[i].coef==0)//一定要考虑等于零的情况,如果等于零,则将该项删除vec1.erase(vec1.begin()+i);flag=1;//设置标志为1}}for(int i=0;i<vec1.size();i++)//用索引,如果用迭代器则再插入元素后,迭代器失效,{if(flag==1){break;}if((vec1[i]).expo<expo)//第二种情况,第二个多项式中的某一项在第一个多项式中没有,则直接将该项插入相应的位置{flag1=0;plo plo1;plo1.expo=expo;plo1.coef=coef;vec1.insert(vec1.begin()+i,plo1);break;}}if(flag1==1&&flag!=1)//第三种情况,第二个多项式中的某一项直接放在向量的最后面,如1 100 3.0,2 30 3.0 20 2.0{plo plo1;plo1.expo=expo;plo1.coef=coef;vec1.push_back(plo1);}}num2--;}cout<<vec1.size();//输出时候要注意最后面一个不要空格,当相加后的结果为0时,直接输出0即可if(vec1.size()!=0){cout<<' ';}for(iter=vec1.begin();iter!=vec1.end();iter++){cout<<(*iter).expo<<" "<<fixed<<setprecision(1)<<(*iter).coef;if(iter<vec1.end()-1)cout<<" ";}}

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