Pku oj 2159 Ancient Cipher(字符串）

Ancient Cipher

Time Limit: 1000MS Memory Limit: 65536KTotal Submissions: 32274 Accepted: 10483

Description

Ancient Roman empire had a strong government system with various departments, including a secret service department. Important documents were sent between provinces and the capital in encrypted form to prevent eavesdropping. The most popular ciphers in those times were so called substitution cipher and permutation cipher.
Substitution cipher changes all occurrences of each letter to some other letter. Substitutes for all letters must be different. For some letters substitute letter may coincide with the original letter. For example, applying substitution cipher that changes all letters from 'A' to 'Y' to the next ones in the alphabet, and changes 'Z' to 'A', to the message "VICTORIOUS" one gets the message "WJDUPSJPVT".
Permutation cipher applies some permutation to the letters of the message. For example, applying the permutation <2, 1, 5, 4, 3, 7, 6, 10, 9, 8> to the message "VICTORIOUS" one gets the message "IVOTCIRSUO".
It was quickly noticed that being applied separately, both substitution cipher and permutation cipher were rather weak. But when being combined, they were strong enough for those times. Thus, the most important messages were first encrypted using substitution cipher, and then the result was encrypted using permutation cipher. Encrypting the message "VICTORIOUS" with the combination of the ciphers described above one gets the message "JWPUDJSTVP".
Archeologists have recently found the message engraved on a stone plate. At the first glance it seemed completely meaningless, so it was suggested that the message was encrypted with some substitution and permutation ciphers. They have conjectured the possible text of the original message that was encrypted, and now they want to check their conjecture. They need a computer program to do it, so you have to write one.

Input

Input contains two lines. The first line contains the message engraved on the plate. Before encrypting, all spaces and punctuation marks were removed, so the encrypted message contains only capital letters of the English alphabet. The second line contains the original message that is conjectured to be encrypted in the message on the first line. It also contains only capital letters of the English alphabet.
The lengths of both lines of the input are equal and do not exceed 100.

Output

Output "YES" if the message on the first line of the input file could be the result of encrypting the message on the second line, or "NO" in the other case.

Sample Input

JWPUDJSTVPVICTORIOUS

Sample Output

YES

Source

Northeastern Europe 2004

题很长。。但是贼水的一道题，就是问你能不能由上面字符串变到下面字符串，每个字符可以随便变，但相同字符只能变成相同的字符，本来想用map写，但一看是字符，直接标记数组然后排序比较对应位是否相等就ac

#include<cstdio>#include<iostream>#include<map>#include<cstring>#include<algorithm>using namespace std;int main(){char a[105];char b[105];int c[26];int d[26];while(~scanf("%s",&a)){scanf("%s",&b);int flag = 0;int len = strlen(a);int len2 = strlen(b);if(len2 != len){printf("NO\n");break;}memset(c,0,sizeof(c));memset(d,0,sizeof(d));for(int i=0;i<len;i++){c[a[i] - 'A']++;}for(int i=0;i<len;i++){d[b[i] - 'A']++;}sort(c,c+26);sort(d,d+26);for(int i=0;i<26;i++){if(c[i] != d[i]){flag = 1;printf("NO\n");break;}}if(flag == 0)printf("%YES\n");}}