CodeForces 616A Comparing Two Long Integers【字符串】

A. Comparing Two Long Integers

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

You are given two very long integers a, b (leading zeroes are allowed). You should check what number a or b is greater or determine that they are equal.

The input size is very large so don't use the reading of symbols one by one. Instead of that use the reading of a whole line or token.

As input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriterinstead of Scanner/System.out in Java. Don't use the function input() in Python2 instead of it use the function raw_input().

Input

The first line contains a non-negative integer a.

The second line contains a non-negative integer b.

The numbers a, b may contain leading zeroes. Each of them contains no more than 106 digits.

Output

Print the symbol "<" if a < b and the symbol ">" if a > b. If the numbers are equal print the symbol "=".

Examples

input

910

output

<

input

1110

output

>

input

0001234512345

output

=

input

01239

output

>

input

0123111

output

>

题意：

给出两个有前导零的大数，判断两者的大小关系

题解：

比较的时候需要跳过前导零，使用指针比较方便，注意是是大数的比较，先比较位数，位数相同的话，直接按位比较就行了..

/*http://blog.csdn.net/liuke19950717*/#include<cstdio>#include<cstring>#include<algorithm>using namespace std;const int maxn=1e6+5;char a[maxn],b[maxn];void change(char *&p)//去掉前导零的操作{while(*p=='0'){++p;}}char slove(){char *pa=a,*pb=b;change(pa);change(pb);int lena=strlen(pa),lenb=strlen(pb);if(lena==lenb)//位数相同{int tp=strcmp(pa,pb);if(tp==0){return '=';}else if(tp==1){return '>';}else{return '<';}}else if(lena<lenb){return '<';}return '>';}int main(){while(~scanf("%s%s",a,b)){printf("%c\n",slove());}return 0;}